Lines AB and CD intersect at a point O in such a way that ∠DOB = 5∠COB. What is ∠AOD?
Angles DOB and COB are supplementary ---> angle(DOB) + angle(COB) = 180o.
Since angle(DOB) = 5 · angle(COB) ---> 5 · angle(COB) + angle(COB) = 180o
---> 6 · angle(COB) = 180o ---> angle(COB) = 30o
Since angle(AOD) = angle(COB) ---> angle(AOD) = 30o