+0  
 
-1
374
1
avatar

In parallelogram ABCD , diagonals AC⎯⎯⎯⎯⎯ and BD⎯⎯⎯⎯⎯ intersect at point E, BE=2x2−3x , and DE=x2+10 .

What is BD ?

 

Enter your answer in the box.

 units

Guest Dec 13, 2017
 #1
avatar+92608 
+1

The diagonals of a parallelogram bisect each other....therefore

 

2x^2 -3x  = x^2 + 10    simplify

 

x^2 - 3x - 10  = 0    factor

 

(x -5)(x + 2)   = 0

 

Setting each linear factor to 0 and solving for x....we have two possibilities, x  = 5  or x  = - 2

 

If  x  = 5,  BD  =  2 [ (5)^2 + 10 ]  =  70

 

If x  = -2, BD  = 2 [ (-2)^2 + 10 ] =  28

 

 

cool cool cool

CPhill  Dec 13, 2017

35 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.