each of equal sides of an isosceles triangle is 4cm greater than its height .If the base of triangle is 24 cm ,calculate the perimeter and the area of the triangle
+1223 The base is 24 centimeters, so the legs are 28 centimeters each. So, the perimeter is 24 + 2(28) = 80 centimeters.
The height of the triangle is \(\sqrt{28^2 - 12^2} = 8\sqrt{10}.\) That makes the area \(\frac{1}{2}(8\sqrt{10})(24) = \boxed{96\sqrt{10}}\) cm^2.
