+2653 In triangle $PQR,$ $M$ is the midpoint of $\overline{QR}.$ Find $PM.$
PQ = 5, PR = 8, QR = 11
+1926 First, let's set a variable. Let's set x as angle PQR.
From the problem, we can write that
\(cos(x) = \frac{8^2 + 11² - 5²}{2*8*11}=10/11\)
Now, we can sue the law of cosines to write
\( (PM)² = 5.5² + 8² - 2*5.5*8 * cos(x)\\ \)
Now, we can find PM.
\(PM^2 = 10/11*6.25\\ PM \approx 2.38365647311\)
I'm not exactly sure if this is correct. I may have made a mistake.
Thanks! :)
