+0  
 
0
77
1
avatar

In triangle ABC, AC = BC, angle DCB is 40 degrees, and CD is parallel to AB. What is the number of degrees in angle ACB?

 

 Jun 2, 2021
 #1
avatar+121056 
+1

If DCB  = 40°......then BC  is  a transversal  cutting parallels CD  and  AB

So  angle CBA =  angle  DCB

And  since AC = BC,  then  angle  CAB  =  angle CBA  =   40°

 

So...angle  ACB =  180  - 2(40)  =  180 -  80   =  100°  

 

 

cool cool cool

 Jun 2, 2021

22 Online Users

avatar
avatar