Let $IJKLMN$ be a hexagon with side lengths $IJ = LM = 3,$ $JK = MN = 3,$ and $KL = NI = 3$. Also, all the interior angles of the hexagon are equal. Find the area of hexagon $IJKLMN$.
Let $IJKLMN$ be a hexagon with side lengths $IJ = LM = 3,$ $JK = MN = 3,$ and $KL = NI = 3$. Also, all the interior angles of the hexagon are equal. Find the area of hexagon $IJKLMN$.
The sides are equal and the angles are equal.
That means the hexagon is a regular hexagon.
3 sqrt(3)
The area of a regular hexagon in terms of its sides is A = –––––––– x a2 where "a" is a side.
2
A = ( 3 x sqrt(3) x 32 ) / 2
A = ( 27 sqrt(3) ) / 2
Is that good enough or do you need a number.
A = ( 27 x 1.732 ) / 2
A = 23.383
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