In triangle ABC, CA=4sqrt(2), CB=4sqrt(6), and A=60 degrees. What is B in degrees?
30 degrees = B
sin a / (4 sqrt6) = sin b / (4 sqrt 2)
sin b = sin a / (4 sqrt 6) * 4 sqrt 2
=1/2
b = arcsin(1/2 ) = 30 degrees
