+330 Altitudes AD and BE of acute triangle ABC intersect at point H. If angle ABH = 30 and angle DAC = 45, then what is angle HCA in degrees?
+1908 Let's start with what we should do for any geometry question, which is to of course, graph it.
Note that we have right triangles ADC, ABE, ABD, BHD, BEC and triangles ABE and ADC are a 30-60-90 and a 45-45-90 respectively.
Now, it's pretty simple from here.
We first draw the altitude for triangle ABC from point C to line segment AB, it intersects point H along the way.
Also, since we know BAC is 60 degrees, HCA would be 30 degrees!
30 degrees!
Thanks!
+1908 Let's start with what we should do for any geometry question, which is to of course, graph it.
Note that we have right triangles ADC, ABE, ABD, BHD, BEC and triangles ABE and ADC are a 30-60-90 and a 45-45-90 respectively.
Now, it's pretty simple from here.
We first draw the altitude for triangle ABC from point C to line segment AB, it intersects point H along the way.
Also, since we know BAC is 60 degrees, HCA would be 30 degrees!
30 degrees!
Thanks!
