In the figure below, PQRS is a parallelogram of perimeter 24 and area 28. What is the perimeter of rectangle QOST? Include an explanation of how you solved the problem.
+128474 If the perimeter of PQRS is 24, then PS = QR = (24 - 14)/ 2 = 10/2 = 5
And the area would be the ST x PS = 28
So ST x 5 = 28 divide both sides by 5
ST = 28/5 = 5.6
And RT =√[RS^2 - ST^2] = √[7^2 - 5.6^2 ] = √17.64 = 4.2
So RT + QR = 4.2 + 5 = 9.2 = QT
So the perimeter of rectangle QOST = 2(ST + QT) = 2(5.6 + 9.2) = 29.6 units
