Triangle ABC has the height AD and angle A = 90º. If CD = 4, and BD = \(5\), find this ratio [ACD]/[ABD].
Triangle ABC has the height AD and angle A = 90º. If CD = 4, and BD = 5, find this ratio [ACD]/[ABD].
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AD = x
√(42+x2) * √(52+x2) = 9x
AD = 2√5
[ACD] / [ABD] = 4/5