The perimeter of a particular rectangle is eight times its width. If the area of the rectangle is 24 in^2, what is the width of the rectangle, in inches?

Guest Sep 6, 2021

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*The perimeter of a particular rectangle is eight times its width. If the area of the rectangle is 24 in^2, what is the width of the rectangle, in inches?*

Call the perimeter P, the length L, and the width W.

P = 8W given

P = 2L + 2W perimeter is L+W+L+W

8W = 2L + 2W

6W = 2L

3W = L

A = L • W

A = 3W • W

A = 3W^{2}

24 = 3W^{2}

8 = W^{2}

W = sqrt(8) = **2•sqrt(2)**

The problem doesn't ask for the length, but by the way **L = 6•sqrt(2)**

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Guest Sep 7, 2021