A right triangle has legs of length 6 and b and a hypotenuse of length c . The perimeter of the triangle is 12. Compute c.
+2401 c = c
b = 6 - c
6^2 + (6 - c)^2 = c^2
36 + 36 - 12c + c^2 = c^2
72 = 12c
c = 6
=^._.^=
+36916 Hypotenuse cannot be the same length as one of the legs.....
sooo
6 + a +c = 12
6^2 +a^2 = c^2 or c = sqrt (36 + a2 ) sub this into the forst equation
6 + a + sqrt (36+a^2) = 12
sqrt(36+a^2) = 6-a
36 + a^2 = 36 - 12a + a^2 uh oh....this is not a right triangle possibiity !
Guess I should have seen that ....if the hyptotenuse has to be longer than the leg of 6 the perimiter will be greater than 12 !
