In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.

LiIIiam0216 Jun 21, 2024

#1**+1 **

Let's note some really important things about this problem.

If \(AD = AB\), then we have \(\angle ABD = \angle ADB\)

From this, we can write the equation

\(\angle ABD = (180 - 17) / 2 = 81.5° \)

So our answer is just 81.5

Thanks! :)

NotThatSmart Jun 21, 2024