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In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.

 Jun 21, 2024
 #1
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Let's note some really important things about this problem. 

If \(AD = AB\), then we have \(\angle ABD = \angle ADB\)

 

From this, we can write the equation

\(\angle ABD = (180 - 17) / 2 = 81.5° \)

 

So our answer is just 81.5

 

Thanks! :)

 Jun 21, 2024

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