+2729 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+1950 Let's note some really important things about this problem.
If AD=AB, then we have ∠ABD=∠ADB
From this, we can write the equation
∠ABD=(180−17)/2=81.5°
So our answer is just 81.5
Thanks! :)
