+2653 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+1876 Let's note some really important things about this problem.
If \(AD = AB\), then we have \(\angle ABD = \angle ADB\)
From this, we can write the equation
\(\angle ABD = (180 - 17) / 2 = 81.5° \)
So our answer is just 81.5
Thanks! :)
