Triangle DEF is equilateral. Find AE.DA = 3, AF = 2
We can use the Law of Cosines to solve this problem. Applying it, the law states that
AE2=AF2+FE2−2(AF∗FE)cos(60°)
Now, plugging in the values from the problem we already know, we find that
AE2=22+52−2(2∗5)(1/2)AE2=19AE=√19
Thanks! :)