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Let XY be a tangent to a circle, and let XBA be a secant of the circle, as shown below. If AX = 16 and XY = 9, then what is AB?

 

 Jun 8, 2021
 #1
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x is AB

There's a formula, it's called the "tangent secant theorem" or something, I don't really remember. Anyways, in this case, the formula says that: 

9^2=16x

So AB=81/16

Tell me if I'm wrong though, I might have remembered the formula incorrectly

 

JP

 Jun 8, 2021
 #2
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XY = 9          AX = 16          AX = 16         

 

(XY)2 = (BX)(AX)

 

81 = 16(BX)

 

BX = 51/16

 

AB = 1015/16

 Jun 9, 2021

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