Let XY be a tangent to a circle, and let XBA be a secant of the circle, as shown below. If AX = 16 and XY = 9, then what is AB?

Guest Jun 8, 2021

#1**0 **

x is AB

There's a formula, it's called the "tangent secant theorem" or something, I don't really remember. Anyways, in this case, the formula says that:

9^2=16x

So AB=**81/16**

Tell me if I'm wrong though, I might have remembered the formula incorrectly

JP

JKP1234567890 Jun 8, 2021