Let XY be a tangent to a circle, and let XBA be a secant of the circle, as shown below. If AX = 16 and XY = 9, then what is AB?
+208 x is AB
There's a formula, it's called the "tangent secant theorem" or something, I don't really remember. Anyways, in this case, the formula says that:
9^2=16x
So AB=81/16
Tell me if I'm wrong though, I might have remembered the formula incorrectly
JP
