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Let $WXYZ$ be a trapezoid with bases $\overline{XY}$ and $\overline{WZ}$. In this trapezoid, $\angle ZXW = 120^\circ$, $\angle XWZ = 60^\circ$, and $\angle XYZ = 120^\circ$. Find $\angle YXZ$, in degrees.

 Jul 2, 2024

Best Answer 

 #1
avatar+1267 
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First, let's note something really important. 

If \(\angle XWZ = 60°\), then we must have that \(\angle WXY = 180° - 60° = 120°\) since

XY and WZ are parralel lines. 

 

However, this also means that \(\angle ZXW\) must be less than 120 degrees. 

In the problem though, it states that \(\angle ZXW = 120^\circ\)

 

Therefore, this question is invalid/ 

 

This problem is not possible or solvable. 

 

Thanks! :)

 Jul 2, 2024
 #1
avatar+1267 
+1
Best Answer

First, let's note something really important. 

If \(\angle XWZ = 60°\), then we must have that \(\angle WXY = 180° - 60° = 120°\) since

XY and WZ are parralel lines. 

 

However, this also means that \(\angle ZXW\) must be less than 120 degrees. 

In the problem though, it states that \(\angle ZXW = 120^\circ\)

 

Therefore, this question is invalid/ 

 

This problem is not possible or solvable. 

 

Thanks! :)

NotThatSmart Jul 2, 2024

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