+1724 Let $WXYZ$ be a trapezoid with bases $\overline{XY}$ and $\overline{WZ}$. In this trapezoid, $\angle ZXW = 120^\circ$, $\angle XWZ = 60^\circ$, and $\angle XYZ = 120^\circ$. Find $\angle YXZ$, in degrees.
+1837 First, let's note something really important.
If \(\angle XWZ = 60°\), then we must have that \(\angle WXY = 180° - 60° = 120°\) since
XY and WZ are parralel lines.
However, this also means that \(\angle ZXW\) must be less than 120 degrees.
In the problem though, it states that \(\angle ZXW = 120^\circ\)
Therefore, this question is invalid/
This problem is not possible or solvable.
Thanks! :)
+1837 First, let's note something really important.
If \(\angle XWZ = 60°\), then we must have that \(\angle WXY = 180° - 60° = 120°\) since
XY and WZ are parralel lines.
However, this also means that \(\angle ZXW\) must be less than 120 degrees.
In the problem though, it states that \(\angle ZXW = 120^\circ\)
Therefore, this question is invalid/
This problem is not possible or solvable.
Thanks! :)
