Let $WXYZ$ be a trapezoid with bases $\overline{XY}$ and $\overline{WZ}$. In this trapezoid, $\angle ZXW = 120^\circ$, $\angle XWZ = 60^\circ$, and $\angle XYZ = 120^\circ$. Find $\angle YXZ$, in degrees.

ABJeIIy Jul 2, 2024

#1**+1 **

First, let's note something really important.

If \(\angle XWZ = 60°\), then we must have that \(\angle WXY = 180° - 60° = 120°\) since

XY and WZ are parralel lines.

However, this also means that \(\angle ZXW\) must be less than 120 degrees.

In the problem though, it states that \(\angle ZXW = 120^\circ\)

Therefore, this question is invalid/

This problem is not possible or solvable.

Thanks! :)

NotThatSmart Jul 2, 2024

#1**+1 **

Best Answer

First, let's note something really important.

If \(\angle XWZ = 60°\), then we must have that \(\angle WXY = 180° - 60° = 120°\) since

XY and WZ are parralel lines.

However, this also means that \(\angle ZXW\) must be less than 120 degrees.

In the problem though, it states that \(\angle ZXW = 120^\circ\)

Therefore, this question is invalid/

This problem is not possible or solvable.

Thanks! :)

NotThatSmart Jul 2, 2024