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# Geometry

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Let $WXYZ$ be a trapezoid with bases $\overline{XY}$ and $\overline{WZ}$. In this trapezoid, $\angle ZXW = 120^\circ$, $\angle XWZ = 60^\circ$, and $\angle XYZ = 120^\circ$. Find $\angle YXZ$, in degrees.

Jul 2, 2024

#1
+1267
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First, let's note something really important.

If $$\angle XWZ = 60°$$, then we must have that $$\angle WXY = 180° - 60° = 120°$$ since

XY and WZ are parralel lines.

However, this also means that $$\angle ZXW$$ must be less than 120 degrees.

In the problem though, it states that $$\angle ZXW = 120^\circ$$

Therefore, this question is invalid/

This problem is not possible or solvable.

Thanks! :)

Jul 2, 2024

#1
+1267
+1

First, let's note something really important.

If $$\angle XWZ = 60°$$, then we must have that $$\angle WXY = 180° - 60° = 120°$$ since

XY and WZ are parralel lines.

However, this also means that $$\angle ZXW$$ must be less than 120 degrees.

In the problem though, it states that $$\angle ZXW = 120^\circ$$

Therefore, this question is invalid/

This problem is not possible or solvable.

Thanks! :)

NotThatSmart Jul 2, 2024