Let AB be a diameter of a circle. Let C and D be points on the circle, on opposite sides of diameter AB. If OA = 5, and BC = 6, then find tan angle BDC.
Let AB be a diameter of a circle. Let C and D be points on the circle, on opposite sides of diameter AB. If OA = 5, and BC = 6, then find tan angle BDC.
AB = 10
BC = 6
If C and D are on opposite sides on a circle (180º apart from each other), then AD = 6
BC is one leg of the right triangle, line segment CD (diameter) is the hypotenuse, and BD is the second leg.
CD = 2 * OA = 10
Let angle BDC be β sin(β) = BC / CD
β = 36.86989765º