Let AB be a diameter of a circle. Let C and D be points on the circle, on opposite sides of diameter AB. If OA = 5, and BC = 6, then find tan angle BDC.

Guest May 19, 2020

#1**0 **

Let AB be a diameter of a circle. Let C and D be points on the circle, on opposite sides of diameter AB. If OA = 5, and BC = 6, then find tan angle BDC.

AB = 10

BC = 6

If C and D are on opposite sides on a circle (180º apart from each other), then AD = 6

BC is one leg of the right triangle, line segment CD (diameter) is the hypotenuse, and BD is the second leg.

CD = 2 * OA = 10

Let angle BDC be **β sin(β) = BC / CD**

** β = 36.86989765º **

Guest May 20, 2020