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Point X is inside rectangle PQRS such that XP = 2, XQ = 10, and XR = 5. Find XS.

 Jun 29, 2022
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For a point - call it X -  inside a rectangle  ( call it PQRS).....the following relationship holds

 

PX^2 +  RX^2 = QX^2 + SX^2

 

2^2   +  5^2   + 10^2 + SX^2 

 

But what you describe is  impossible because   SX^2 =  2^2 + 5^2  -10^2  =  -71

 

But SX is a positive distance......so squaring  it can only produce a poisitve outcome

 

 

cool cool cool 

 Jun 29, 2022

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