The numerical value of a particular square's area is equal to four times the numerical value of its perimeter. What is the length of a side of the square?
Let P = the perimeter = 4S
Area of square = S^2
S^2 = 4 (4S )
S^2 = 16S
S^2 - 16 S = 0
S (S - 16) = 0
S = 16
Let \(l\) be the side length of the square.
So, \(l^2=4 \times 4l\). Simplified: \(l^2=16l\)
Equation's solution is ans
basically L=16
