In triangle $ABC,$ let the angle bisectors be $\overline{BY}$ and $\overline{CZ}$. Given $AB = 14$, $AY = 14$, and $CY = 8$, find $BC$.
A
14
Z Y
8
B C
Because BY is a bisector
BC / CY = AB / AY
BC / 8 = 14 / 14
BC = 8 * 14 / 14 = 8
+868 
