In rectangle ABCD, AD = sqrt(3), P is on AB, and DB and DP trisect angle ADC. Write the perimeter of triangle BDP?
Angle(ADC) = 90o.
Angle(CDB) = 30o.
In triangle(CDB), side DC = sqrt(3) · side(BC) = sqrt(3) · sqrt(3) = 3
Perimeter = sqrt(3) + 3 + sqrt(3) + 3 = ...
Perimeter of triangle BDP = 4 + 2√3
