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In rectangle ABCD, AD = sqrt(3), P is on AB, and DB and DP trisect angle ADC. Write the perimeter of triangle BDP?

 

 Feb 6, 2022
 #1
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Angle(ADC) = 90o.

Angle(CDB) = 30o.

 

In triangle(CDB), side DC = sqrt(3) · side(BC)  =  sqrt(3) · sqrt(3)  =  3

 

Perimeter = sqrt(3) + 3 + sqrt(3) + 3  =  ...

 Feb 6, 2022
 #2
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Perimeter of triangle BDP = 4 + 2√3

 Feb 7, 2022

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