Harriet has a square piece of paper.
She folds it in half to form a rectangle and then in half again to form a second rectangle (which is a square).
The perimeter of the second rectangle is 30 cm
What is the area of the original square?
The second rectangle would have dimensions of 7.5 each, since it is a square. We double that because the sides have been folded in half for each side to get a 15 by 15 square. 15*15 is 225.
I got this answer from here: https://brainly.in/question/18756313
Let say Side of original Square
= 4A cm
Hence Area = (4A)² = 16A² cm²
Square when folded in half
Then Sides of rectangle
will be 4A & 2A
Now again Folded
Sides can be 2A & 2A or 4A & A
2A & 2A would be a Square ( its given that its not a square)
Hence Second Rectangle Sides are 4A & A
Perimeter = 2(4A + A) = 10A
10A = 30cm
=> A = 3 cm
Area of the original square = 16A² = 16 * 3² = 144 cm²
area of the original square = 144 cm²
hihihi, this line introduces the error: "( its given that its not a square)" after the second fold.
on the contrary, it's given that after the second fold the figure is a square, specifically
the problem states that: "second rectangle (which is a square)" after the second fold.