+207 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+1908 First, let's note that if AD = AB, then \(\angle ADB = \angle ABD\)
So, this means we have \(ABD = (180 - 17) / 2 = 81.5° \)
Our final answer is thus 81.5
Thanks! :)
