In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.

BRAlNBOLT Jun 12, 2024

#1**+1 **

First, let's note that if AD = AB, then \(\angle ADB = \angle ABD\)

So, this means we have \(ABD = (180 - 17) / 2 = 81.5° \)

Our final answer is thus 81.5

Thanks! :)

NotThatSmart Jun 12, 2024