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In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.

 Jun 12, 2024
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First, let's note that if AD = AB, then \(\angle ADB = \angle ABD\)

 

So, this means we have \(ABD = (180 - 17) / 2 = 81.5° \)

 

Our final answer is thus 81.5

 

Thanks! :)

 Jun 12, 2024

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