In triangle PQR, M is the midpoint of PQ. Let X be the point on QR such that PX bisects angle QPR, and let the perpendicular bisector of PQ intersect AX at Y. If PQ = 36, PR = 22, QR = 26, and MY = 8, then find the area of triangle PQR
PQ = 36, PR = 22, QR = 26 ..... This is all we need to know
→ semi-perimeter = [ 36 + 22 + 26 ] / 2 = 42....using Heron's Formula
[ PQR] = sqrt [ 42 * 6 * 16 * 20 ] = 48 sqrt 35 ≈ 284
+153 
