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Let $IJKLMN$ be a hexagon with side lengths $IJ = LM = 3,$ $JK = MN = 3,$ and $KL = NI = 3$. Also, all the interior angles of the hexagon are equal. Find the area of hexagon $IJKLMN$.

 Oct 11, 2024
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The first two sentences is just a complicated way of descibing a hexagon with a side length of 3. The area of a hexagon with a side length n is\(\frac{3\sqrt{3}}{2}n^2\)

 

Therefore,

 

\(A = \frac{3\sqrt{3}}{2}6^2\)

\(=\frac{3\sqrt{3}}{2}36\)

\(3\sqrt{3}(18)\)

\(=\mathbf{54\sqrt{3}}\)

 Oct 11, 2024

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