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Find the area of an isosceles triangle with two legs of length 8 and base of length $4$.

 Dec 9, 2021
 #1
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1/2 * 8 * 4 = 16 units^2

 Dec 9, 2021
 #2
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Be careful... it's not a right triangle :)

Drawing an altitude, we get the length to be √(8^2 - 2^2) = 2√15. 

2√15 * 4/2 = 4√15.

 Dec 9, 2021

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