Find the area of an isosceles triangle with two legs of length 8 and base of length $4$.
1/2 * 8 * 4 = 16 units^2
Be careful... it's not a right triangle :)
Drawing an altitude, we get the length to be √(8^2 - 2^2) = 2√15.
2√15 * 4/2 = 4√15.
+133 
