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In the diagram below, the area of triangle BCD is 80. What is the area of triangle BAD?

 

 Mar 25, 2021
 #1
avatar+117787 
+2

BC is  the height of triangle  BCD

 

So

 

80   = (1/2) CD * BC

 

160 = 15 * BC

 

160 / 15  = BC = 32/3

 

And ABCD is a trapezoid...so its area  =

 

(1/2) BC *  ( AB + CD)  =

 

(1/2) (32/3)  ( 9 + 15)  =

 

(1/2) ( 32/3) (24)  =

 

128

 

So....area of triangle BAD =  [ABCD  ] - [ BCD ] =   128  -  80   =   48

 

 

cool cool cool

 Mar 25, 2021
 #2
avatar+1164 
+3

[BAD] = {(160 / 15) * 1/2(9 + 15)} - 80 = 48

 Mar 25, 2021

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