Points $A$ and $B$ are on side $\overline{YZ}$ of rectangle $WXYZ$ such that $\overline{WA}$ and $\overline{WB}$ trisect $\angle ZWX$. If $WX = 2$ and $XY = 3$, then what is the area of rectangle $WXYZ$?
You are given the dimensions of the rectangle directly, the area is of course \(WX \cdot XY = 2 \cdot 3 = 6\).
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