In triangle ABC, the angles $\angle A,$ $\angle B,$ $\angle C$ form an arithmetic sequence. If \angle A = 60^\circ, then what is $\angle C,$ in degrees?
We can rewrite the angles as $\angle A = 60^\circ$, $\angle B = 60^\circ+x$, and $\angle C = 60^\circ+2x$. Now, we can use the Triangle Sum Theorem to solve for $x$. We can make the equation $60+60+x+60+2x=180$ Solving for $x$ gets $x=0$, so therefore all of the angles are $60^\circ$ so $\angle C = 60^\circ$.
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