geometry

if $ \overset{-}{BC} = \overset{-}{CD}$ -- that doesnt make any sense! point D cuts $ \overset{-}{BC} $ so it just wouldnt work... unless i am missing somehting.

                  A=  49

B            D                C   

Agree  with  UTS.....if D is on BC, then    BC   cannot =  CD

D is on side BC of triangle ABC. We know ABC ~ ACD and angle A = 49 degrees.  If BD = CD, what is angle B in degrees? 

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After a small correction, this becomes a very challenging question.