Quadrilateral ABCD is a circumscribed quadrilateral, meaning that it is circumscribed about a circle, so the circle is tangent to all four sides of ABCD. Show that AB + CD = BC + AD.
nevermind, i think i got it;
heres how i did it
first draw quadrilateral ABCD, then draw the circle inside. start labeling the equal tangents from vertices. also label the points of tangency. I labeled mine
like this: W on AB, X on BC, Y on DC, and Z on AD. AW = AZ = x (variables), BX = WB = y, XC = YC = z, and ZD = DY = w.
the equation is x + y + w + z = x + w + y + z
which is true
proved
this solution made no sense i know
