what is the equation of the line that passes through(1,2) and is parallel to the line that passes through the(0,5) and (-4,8)

The line that passes through (0,5) and (-4,8) has the slope (y_{2-}y_{1})/(x_{2-}x_{1}) = (8-5)/(-4-0) = 3/-4 = -3/4

y = mx + b, plug in the point (1,2):

2 = (-3/4)(1) + b

2 = -3/4 + b

b = 2.75

y = (-3/4)x + 2.75

The slope of the line passing through (0, 5) and (-4, 8) is given by

[ 8 - 5 ] / [ -4 - 0 ] = 3/-4 = -3/4

A line parallel to this has the same slope so we have

y = (-3/4) ( x - 1) + 2 simplify

y = (-3/4)x + 3/4 + 2

y = (-3/4)x + 3/4 + 8/4

y = (-3/4)x + 11/4