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what is the equation of the line that passes through(1,2) and is parallel to the line that passes through the(0,5) and (-4,8)

 Mar 4, 2019
 #1
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The line that passes through (0,5) and (-4,8) has the slope (y2-y1)/(x2-x1) = (8-5)/(-4-0) = 3/-4 = -3/4

y = mx + b, plug in the point (1,2):

2 = (-3/4)(1) + b

2 = -3/4 + b

b = 2.75

 

y = (-3/4)x + 2.75

 Mar 4, 2019
 #2
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The slope of the line passing through  (0, 5)  and (-4, 8) is given by

[ 8 -  5 ] / [ -4 - 0 ]  =   3/-4  = -3/4

 

A line parallel to this has the same slope so we have

 

y = (-3/4) ( x - 1) + 2       simplify

 

y = (-3/4)x + 3/4 + 2

 

y = (-3/4)x + 3/4 + 8/4

 

y = (-3/4)x + 11/4

 

 

cool cool cool

 Mar 4, 2019

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