The differences between the hypotenuse and the other two sides of a right triangle are 8 and 4. Find the perimeter of the triangle.
hyp^2 = (hyp-4)^2 + (hyp-8)^2
h^2 -8h +16 + h^2 - 16h + 64
h^2 +24h -80 = 0 quadratic formula h = 4, 20 throw out 4 hyp = 20 leg1 = 12 leg2 = 16 20 + 12 + 16 = perimeter
hyp^2 = (hyp-4)^2 + (hyp-8)^2
h^2 -8h +16 + h^2 - 16h + 64
h^2 +24h -80 = 0 quadratic formula h = 4, 20 throw out 4 hyp = 20 leg1 = 12 leg2 = 16 20 + 12 + 16 = perimeter