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Let ABCD be a square.  Let P be a point outside square ABCD such that triangle ABP is equilateral.  Find BPD in degrees.

 Dec 20, 2023
 #1
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         P

 

 

A                  B

 

 

C                 D

 

Angle ABP  = 60

Angle ABD = 90

Angle PBD = 60 + 90  = 150

 

In triangle PBD , BP = BD

So angle BDP  = angle BPD

 

So angle BPD =   (180 - 150) / 2 =  30 / 2  =  15°

 

 

cool cool cool

 Dec 20, 2023

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