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In triangle $ABC$, $M$ is the midpoint of $\overline{BC}$, and $N$ is the midpoint of $\overline{AC}$.  The perpendicular bisectors of $BC$ and $AC$ intersect at a point $O$ inside the triangle.  If $\angle AOB = 90^\circ$, then find the measure of $\angle MON$, in degrees.

 Apr 11, 2024
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Find the measure of MON in degrees.

 

CAO+CBO=45° | peripheral  to 90° (AOB)MON=90°CAO+90°CBO=180°(CAO+CBO)=180°45°MON=135°

 

laugh  !

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 Apr 13, 2024
edited by asinus  Apr 13, 2024

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