+569 Points $A$ and $B$ are on side $\overline{YZ}$ of rectangle $WXYZ$ such that $\overline{WA}$ and $\overline{WB}$ trisect $\angle ZWX$. If $WX = 2$ and $XY = 3$, then what is the area of rectangle $WXYZ$?
+1946 This problem actually has a very simple answer.
Let's note the two sidelengths given, We have WX=2 and XY=3
In order to find the area of WXYZ, we must find the height and base.
The base of the rectange is WX and the height of rectangle is XY
The problem gave all the dimensions we need to already solve this problem. We have
WX⋅XY=2⋅3=6
So our final answer is 6.
Thanks! :)
