In triangle $ABC,$ $\angle B = 90^\circ.$ Point $X$ is on $\overline{AC}$ such that $\angle BXA = 90^\circ,$ $BC = 15,$ and $CX = 5$. What is $BX$?
BX = 20*sqrt(7)
https://web2.0calc.com/questions/right-triangles_33
+1518 
