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In triangle $ABC,$ $\angle B = 90^\circ.$ Point $X$ is on $\overline{AC}$ such that $\angle BXA = 90^\circ,$ $BC = 15,$ and $CX = 5$. What is $BX$?

 Jun 22, 2024
 #1
avatar+1710 
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BX = 20*sqrt(7)

 Jun 22, 2024
 #2
avatar+129725 
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https://web2.0calc.com/questions/right-triangles_33

 

 

cool cool cool

 Jun 22, 2024

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