Help plz with geometry
In triangle ABC, the angle bisector of angle BAC meets BC at D. If angle BAC = 60, angle ABC = 60, and AD = 24, then find the area of triangle ABC.
+132 So this should be an equilateral triangle since two angles are 60 degrees. This means BD + CD = BC = AB =DC. The sin(60) is sqrt(3)/2. So if AD=24, then each side of the equilateral triangle is 16sqrt(3). Doing the triangle area formula of (BH)/2, we get 192 sqrt(3).
