In triangle $ABC,$ the angle bisector of $\angle BAC$ meets $\overline{BC}$ at $D.$ If $\angle BAC = 60^\circ,$ $\angle CAD = 45^\circ,$ and $AD = 24,$ then find the area of triangle $ABC.$
A
15 45
24
B D C
If AD is a bisector and angle BAC = 60
Then angle CAD should be 30 , not 45
+2653 
