In triangle $ABC,$ the angle bisector of $\angle BAC$ meets $\overline{BC}$ at $D.$ If $\angle BAC = 60^\circ,$ $\angle CAD = 45^\circ,$ and $AD = 24,$ then find the area of triangle $ABC.$
A
30 30
B D C
Impossible
If AD is a bisector, then CAD = BAC / 2 = 30
So CAD cannot = 45
+868 
