+0  
 
0
2
1
avatar+729 

In triangle $ABC,$ the angle bisector of $\angle BAC$ meets $\overline{BC}$ at $D.$ If $\angle BAC = 60^\circ,$ $\angle CAD = 45^\circ,$ and $AD = 24,$ then find the area of triangle $ABC.$

 Jun 27, 2024
 #1
avatar+129725 
+1

                      A

               30       30

 

 

B                      D                        C

 

Impossible

If AD is a bisector, then CAD  =  BAC / 2 =   30

So CAD cannot = 45

 

 

cool cool cool

 Jun 27, 2024

4 Online Users

avatar