In right triangle ABC, the hypotenuse AB is 13 units long and leg AC is 5 units long. Point D lies on side AB so that AD = \(10\) units. What is the area of triangle BCD?
+189 90/13 sq units is your answer. triangleABC is a 5-12-13 triangle. area of triangleBCD=(1/2)(BC*DB sin(ABC))=(1/2)(12)(3)(5/13)=6*3*5/13=90/13 so your answer is 90/13 sq units.
