In parallelogram $EFGH,$ let $M$ be the point on $\overline{EF}$ such that $FM:ME = 3:5,$ and let $N$ be the point on $\overline{EH}$ such that $HN:NE = 2:5.$ Line segments $\overline{FH}$ and GN intersect at Q. Find PQ/FH.
+1475 
