Geometry

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What is the trigonometric ratio for sin S as a simplified fraction?

Guest May 3, 2017

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Best Answer

+9481

+3

sin (S) = opposite / hypotenuse

sin (S) = QR / 68

To find the length of QR, we can use the Pythagorean theorem.

QR² + 60² = 68²

QR² = 68² - 60²

QR = \(\sqrt{68^2-60^2}=\sqrt{4624-3600}=\sqrt{1024}=32\)

So..

sin (S) = \(\frac{32}{68}=\frac{8}{17}\) :)

hectictar May 3, 2017

1⁺⁰ Answers

+9481

+3

Best Answer

sin (S) = opposite / hypotenuse

sin (S) = QR / 68

To find the length of QR, we can use the Pythagorean theorem.

QR² + 60² = 68²

QR² = 68² - 60²

QR = \(\sqrt{68^2-60^2}=\sqrt{4624-3600}=\sqrt{1024}=32\)

So..

sin (S) = \(\frac{32}{68}=\frac{8}{17}\) :)

hectictar May 3, 2017

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