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What is the trigonometric ratio for sin S as a simplified fraction?

 

Guest May 3, 2017

Best Answer 

 #1
avatar+7155 
+3

sin (S) = opposite / hypotenuse

sin (S) = QR / 68

 

To find the length of QR, we can use the Pythagorean theorem.

QR2 + 602 = 682

QR2 = 682 - 602

QR = \(\sqrt{68^2-60^2}=\sqrt{4624-3600}=\sqrt{1024}=32\)

 

So..

sin (S) = \(\frac{32}{68}=\frac{8}{17}\)     :)

hectictar  May 3, 2017
 #1
avatar+7155 
+3
Best Answer

sin (S) = opposite / hypotenuse

sin (S) = QR / 68

 

To find the length of QR, we can use the Pythagorean theorem.

QR2 + 602 = 682

QR2 = 682 - 602

QR = \(\sqrt{68^2-60^2}=\sqrt{4624-3600}=\sqrt{1024}=32\)

 

So..

sin (S) = \(\frac{32}{68}=\frac{8}{17}\)     :)

hectictar  May 3, 2017

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