In quadrilateral $BCED$, sides $\overline{BD}$ and $\overline{CE}$ are extended past $B$ and $C$, respectively, to meet at point $A$. If $BD = 8$, $BC = 3$, $CE = 1$, $AC = 19$ and $AB = 13$, then what is $DE$?
CA = 19
BA = 13
BC = 3
This isn't possible
ABC must form a triangle but BC + BA < CA which violates the triangle inequality
+516 
