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In quadrilateral $BCED$, sides $\overline{BD}$ and $\overline{CE}$ are extended past $B$ and $C$, respectively, to meet at point $A$. If $BD = 8$, $BC = 3$, $CE = 1$, $AC = 19$ and $AB = 13$, then what is $DE$?

 Jul 1, 2024
 #1
avatar+129739 
+1

CA = 19

BA = 13

BC = 3

 

This isn't possible

 

ABC must form a triangle but  BC + BA < CA  which violates the triangle inequality

 

cool cool cool 

 Jul 1, 2024

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