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Altitudes $\overline{AD}$ and $\overline{BE}$ of acute triangle $ABC$ intersect at point $H$. If $\angle AHB = 144^\circ$ and $\angle BAH = 66^\circ$, then what is $\angle HCA$ in degrees?

 Jun 3, 2024

Best Answer 

 #1
avatar+806 
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This triangle is impossible to exist. 

 

\(144^\circ + 66^\circ = 210^\circ\), which is more than 180 degrees, what the triangle SHOULD add up to. 

 

Thanks! :)

 Jun 3, 2024
 #1
avatar+806 
+1
Best Answer

This triangle is impossible to exist. 

 

\(144^\circ + 66^\circ = 210^\circ\), which is more than 180 degrees, what the triangle SHOULD add up to. 

 

Thanks! :)

NotThatSmart Jun 3, 2024

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