+826 Altitudes $\overline{AD}$ and $\overline{BE}$ of acute triangle $ABC$ intersect at point $H$. If $\angle AHB = 144^\circ$ and $\angle BAH = 66^\circ$, then what is $\angle HCA$ in degrees?
+1926 This triangle is impossible to exist.
\(144^\circ + 66^\circ = 210^\circ\), which is more than 180 degrees, what the triangle SHOULD add up to.
Thanks! :)
+1926 This triangle is impossible to exist.
\(144^\circ + 66^\circ = 210^\circ\), which is more than 180 degrees, what the triangle SHOULD add up to.
Thanks! :)
