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In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.

 Sep 23, 2024
 #1
avatar+1918 
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Let's note that If AD  = AB  then \( \angle  ABD  =  \angle ADB\)

 

This means that \(\angle ABD = (180 - 17) / 2 = 81.5°\)

 

So 81.5 is the answer. 

 

Thanks! :)

 Sep 24, 2024
edited by NotThatSmart  Sep 24, 2024

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