+1344 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+1826 Let's note that If AD = AB then \( \angle ABD = \angle ADB\)
This means that \(\angle ABD = (180 - 17) / 2 = 81.5°\)
So 81.5 is the answer.
Thanks! :)
