What is the number of square units in the area of trapezoid ABCD with vertices A(0,0), B(0,-2), C(4,0), and D(4,6)?
The area of a trapezoid can be computed as : A = ((b + B) * h ) ÷ 2
B= area of base
If you place the vertices of the trapezoid, you'll notice that b=2, B=6 and h=4. So it would be
((2+6) * 4) ÷ 2 =16
The answer is 16