Angle bisectors AX and BY of triangle meet ABC at point I. Find angle C in degrees, if angle AIB = 103.
In triangle AIB ,
(1/2)A + (1/2)B + angle AIB =180
(1/2) angleA + (1/2) angleB + 103 = 180
(1/2)angleA + (1/2) angleB = 180 -103
(1/2) ( angleA + angle B) = 77 multiply through by 2
angleA + angle B = 154
Angle C = 180 - 154 = 26°
