D is on side BC of triangle ABC. We know $ABC \sim ACD$ and angle A = 49 degrees. If BC = CD, what is angle B in degrees?
+1641 D is on side BC of triangle ABC. We know ABC ~ ACD and angle A = 49 degrees. If BC = CD, what is angle B in degrees?
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Triangle ABC => ∠A = 49º, ∠B = 41º, ∠C = 90º
Triangle ACD => ∠A = 41º, ∠C = 90º, ∠D = 49º
These two triangles are similar!!!
