Let $IJKLMN$ be a hexagon with side lengths $IJ = LM = 3,$ $JK = MN = 3,$ and $KL = NI = 3$. Also, all the interior angles of the hexagon are equal. Find the area of hexagon $IJKLMN$.
We will have 6 congruent triangles with sides of 3 and an included angle of 60°
Area = 6 (1/2) (3^2) * sin 60 =
6 (1/2) (3^2) * sqrt (3) / 2
27 * sqrt (3) / 2 =
13.5 *sqrt (3) ≈ 23.4
+1459 
